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JEE MAIN - Physics (2025 - 22nd January Morning Shift - No. 6)

A line charge of length $\frac{\mathrm{a}^{\prime}}{2}$ is kept at the center of an edge $B C$ of a cube ABCDEFGH having edge length ' $a$ ' as shown in the figure. If the density of line charge is $\lambda \mathrm{C}$ per unit length, then the total electric flux through all the faces of the cube will be ___________ . (Take, $\epsilon_0$ as the free space permittivity)

JEE Main 2025 (Online) 22nd January Morning Shift Physics - Electrostatics Question 14 English

$\frac{\lambda a}{2 \epsilon_0}$
$\frac{\lambda \mathrm{a}}{8 \epsilon_0}$
$\frac{\lambda \mathrm{a}}{4 \epsilon_0}$
$\frac{\lambda \mathrm{a}}{16 \epsilon_0}$

Explicació

JEE Main 2025 (Online) 22nd January Morning Shift Physics - Electrostatics Question 14 English Explanation

$$\phi = {{{q_{enc}}} \over {{\varepsilon _0}}}$$, $${q_{enc}}$$ = enclosed charge

here, we need three other identical cubes to enclose the charge fully.

So, total four cubes enclose the charge

Hence, $${\phi _{cube}} = {\phi \over 4}$$

$$ = {{{q_{enc}}} \over {4{\varepsilon _0}}} = {{\lambda \left( {{a \over 2}} \right)} \over {4{\varepsilon _0}}} \Rightarrow {\phi _{cube}} = {{\lambda a} \over {8{\varepsilon _0}}}$$

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